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Taylor Series Calculator

Taylor Series Calculator

Generate the Taylor series expansion for any function around a specified point. Taylor series are used to approximate complex functions in engineering, physics, and economics. Input your function, select the expansion point, and specify the degree for an accurate series representation, aiding in simplifying complex calculations and approximations.

The intuition behind the Taylor series function is a powerful mathematical tool, used to represent functions with an infinite sum of representing polynomial terms. The Taylor series, named after Brook Taylor, breaks a function into a sum of terms using its derivatives at one point. The Taylor series for e^x, sin(x) and cos(x): Proof & Solutions Here we are going to explore the Taylor series of e^x, sin(x), cos(x), and other examples along with proofs and solutions.

What is the Taylor Series?

The Taylor series of a function \( f(x) \) about a given point \( x = a \) is given by:

\( f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x - a)^2 + \frac{f'''(a)}{3!}(x - a)^3 + \dots \)

In summation form:

\( f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x - a)^n \)

Where:

  • \( f^{(n)}(a) \) is the \( n \)-th derivative of \( f \) evaluated at \( x = a \).
  • \( n! \) is the factorial of \( n \).

If the series is a Maclaurin series, where \( a = 0 \), then it is a special case of the Taylor series.

Common Functions

Taylor Series of \( e^x \)

The function \( e^x \) has derivatives \( f^{(n)}(x) = e^x \). At \( x = 0 \):

\( f^{(n)}(0) = 1 \)

The Taylor series of \( e^x \) centered at \( x = 0 \) (Maclaurin series) is:

\( e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots = \sum_{n=0}^{\infty} \frac{x^n}{n!} \)

Example:

Use the first four terms to approximate \( e^x \) at \( x = 1 \):

If we try to obtain \( e^1 \), it gives us \( e^1 \approx 1 + 1 + \frac{1^2}{2!} + \frac{1^3}{3!} = 1 + 1 + 0.5 + 0.1667 = 2.6667 \)

Taylor Series for \( \sin(x) \)

The function \( \sin(x) \) has derivatives of alternating form \( \sin(x), \cos(x), -\sin(x), -\cos(x) \). At \( x = 0 \):

The trigonometric function \( \sin(0) = 0 \), \( \cos(0) = 1 \).

The Maclaurin series is:

\( \sin(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \dots = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n+1}}{(2n+1)!} \)

Example:

Use the approximate value of \( \sin(\frac{\pi}{6}) \):

\( \sin(\frac{\pi}{6}) \approx \frac{\pi}{6} - \frac{(\frac{\pi}{6})^3}{6} = 0.5236 - 0.0237 = 0.4999 \) (Approx. \( 0.5 \))

The Taylor Series of \( \cos(x) \)

The function \( \cos(x) \) has derivatives \( \cos(x), -\sin(x), -\cos(x), \sin(x) \). At \( x = 0 \):

\( \cos(0) = 1, \quad \sin(0) = 0 \)

The Maclaurin series is:

\( \cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \dots = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{(2n)!} \)

Taylor Series of \( e^{x^2} \)

Let \( f(x) = e^{x^2} \), and every derivative can be computed iteratively from it. At \( x = 0 \):

\( e^{x^2} = 1 + x^2 + \frac{x^4}{2!} + \frac{x^6}{3!} + \dots = \sum_{n=0}^{\infty} \frac{x^{2n}}{n!} \)

Taylor Series Proof

The Taylor series turns a function into an infinite polynomial using its derivatives at one point.

\( f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x - a)^2 + \dots \)

It is done using higher-order derivatives and applying the limiting case where the remainder term tends toward 0 as the number of terms tend toward infinity.

Examples of Taylor Series and Their Solutions

Example 1: Expand \( e^x \) to 3 terms at \( x = 1 \):

\( e^x = 1 + x + \frac{x^2}{2!} \) At \( x = 1 \): \( e^1 \approx 1 + 1 + \frac{1}{2} = 2.5 \)

Example 2: Compute the first three terms of \( \sin(x) \) around \( x = \frac{\pi}{4} \):

\( \sin(x) \approx x - \frac{x^3}{3!} \) At \( x = \frac{\pi}{4} \): \( \sin(\frac{\pi}{4}) \approx \frac{\pi}{4} - \frac{(\frac{\pi}{4})^3}{6} \)

FAQs

What is \( e^x \) Taylor series at \( x = 0 \)?

The Taylor series of \( e^x \) at \( x = 0 \) is:

\( e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots \)

What is \( \sin(x) \) Taylor series?

\( \sin(x) = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n+1}}{(2n+1)!} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \dots

What is \( \cos(x) \) Taylor series?

\( \cos(x) = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{(2n)!} = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \dots

The series expansion of \( e^{x^2} \) at \( x = 0 \):

\( e^{x^2} = \sum_{n=0}^{\infty} \frac{x^{2n}}{n!} = 1 + x^2 + \frac{x^4}{2!} + \dots

If you understand Taylor series, you are equipped with one of the most powerful tools in mathematics to approximate functions, solve equations, and study models in maths.

Published on: 2025-07-05 00:00:00
Author: Taylor Bennett
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